Oct 19, 2016 · I want to read a number from stdin. I don't understand why scanf requires the use of & before the name of my variable: int i; scanf("%d", &i); Why does scanf need the …

This is because in C, functions parameters are passed by value. In order for the scanf() function to modify the ' a ' variable in your main () function, the address of ' a ' shall be given to scanf(), …

Nov 24, 2012 · One way around the problem is to put a blank space before the conversion specifier in the format string: scanf(" %c", &c); The blank in the format string tells scanf to skip …

10 From scanf: On success, the function returns the number of items successfully read. This count can match the expected number of readings or fewer, even zero, if a matching failure …

The first scanf() doesn't return when a user has hit space, even though that's where the number ends (because at that point the line is still in the terminal's line buffer); and the second scanf() …

When the scanf() function completes, the input is pointing at the next newline character. The body of the loop reads and prints that character, so that when the loop restarts, the input is looking …

In case 1, the better solution is, do not mix calls to scanf with other input functions. Either do all your input with scanf, or do all your input with getchar and/or fgets. To do all your input with …

Apr 15, 2017 · This scanf format string consists of two parts: a space character, which skips space characters (' ', '\t', '\n', etcetera) in the input, and the %[^\n] conversion specification, …

Jan 30, 2016 · Read a string as an input using scanf Asked 9 years, 8 months ago Modified 5 years, 10 months ago Viewed 111k times

Others have suggested testing for EOF instead of checking how many items scanf matched. That's fine for this case, where scanf can't fail to match unless there's an EOF, but is not so …